SOLUTION: two metal alloys, containing 26% copper and 54% copper are to be mixed together to get 210 oz that is 30% copper. How much of each should be used?

Question 644755: two metal alloys, containing 26% copper and 54% copper are to be mixed together to get 210 oz that is 30% copper. How much of each should be used?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = ounces of 1st alloy needed
Let = ounces of 2nd alloy needed
given:
= ounces of copper in 1st alloy
= ounces of copper in 2nd alloy
(1)
(2)
-----------------
(1)
(1)
(1)
Multiply both sides of (2) by
and subtract (2) from (1)
(1)
(2)

and, since
(2)
(2)
(2)
180 ounces of 1st alloy are needed
30 ounces of 2nd alloy are needed
check:
(1)
(1)
(1)
(1)
OK

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