SOLUTION: suppose a chemist has 10% and 15% acid solutions in stock. how much of each should the chemist mix if 100ml of a 12% solution is desired?

Question 640393: suppose a chemist has 10% and 15% acid solutions in stock. how much of each should the chemist mix if 100ml of a 12% solution is desired?
Found 2 solutions by sachi, Earlsdon:
Answer by sachi(548) (Show Source): You can put this solution on YOUR website!
let x ml of 10% & 100-x ml of 15% acid soln were mixed to get 100 ml of 12% soln
so 10x/100+15[100-x]/100=12
or 10x+15[100-x]=1200
or -5x=1200-1500=-300
or x=60 ml of 10% & 40 ml of 15% soln were mixed
ans

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
First express the problem in terms of the amount of acid in the acid solutions.
For example, in 10ml of a 10% acid solution, there are 10% of 10ml (0.1(10)) of acid which gives us 1ml of acid.
For this problem, if we lex x = the number of ml of 10% acid solution and (100-x) = the amount of 15% acid solution, we can express the amounts of acid thus:
0.1x+0.15(100-x) = 0.12(100) Simplify and solve for x.
0.1x+15-0.15x = 12
-0.05x+15 = 12 Subtract 15
-0.05x = -3 Divide by -0.05
x = 60ml
The chemist will need to mix 60ml of the 10% acid solution with (100-x = 40)ml of the 15% acid solution to obtain 100ml of 12% acid solution.
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