# SOLUTION: A chemist mixes 10L of a solution that is 30% acid with 30L of a solution that is 50% acid. What is the percent of acid in the new mixture?

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 Question 633939: A chemist mixes 10L of a solution that is 30% acid with 30L of a solution that is 50% acid. What is the percent of acid in the new mixture?Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website! Solution A ========= Amount = 10ml Concentration =30% =0.3 Solution B ========= Amount = 30ml Concentration =50% = 0.5 Mixture ======== Amount =10+30 = 40ml Concentration =x [Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] =[Amount of Mixture *Concentration of Mixture] (10)(0.3)+(30)(0.5)=(40)(x) 3+15=40x 18=40x x=18/40 x=0.45 x=45/100=45% A chemist mixes 10L of a solution that is 30% acid with 30L of a solution that is 50% acid to prepare 40ml mixture that is 45% acid.