SOLUTION: A chemist needs 90 milliliters of a 42% solution but has only 38% and 47% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.

Question 631789: A chemist needs 90 milliliters of a 42% solution but has only 38% and 47% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.
Found 2 solutions by richwmiller, ewatrrr:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
x+y=90;
.38x+.47y=.42*90
x=50 of the 38% y=40 of the 47%
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

Hi,
A chemist needs 90 milliliters of a 42% solution but has only 38% and 47% solutions available.
Set Up on ALL mixture problems is to have the same amount of the key ingredient on both sides of the EQ
Let x represent the amoount of 47% solution
| Solve for x, multiplying EQ thru by 100 first, if you like
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