SOLUTION: Two people leave their homes at 11:30 am and between the two of them, they drive a total of 37.5 miles. one drives an average of 15mph faster then the other . they meet at noon fin

Question 622266: Two people leave their homes at 11:30 am and between the two of them, they drive a total of 37.5 miles. one drives an average of 15mph faster then the other . they meet at noon find the average driving speed for each?
d=rt
d=37.5
t=30 min
let x =rate
x(15) + x * 30 min = 37.5
16x * 30 min = 37.5
I don't know if I am on the right track but I don't know where to go from here
Please help with a formula
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the speed of the slower driver in mi/hr
= the speed of the faster driver
Let = distance driven by slower driver
= distance driven by faster driver
hrs is the time for both drivers
-------------
Slower driver's equation:
(1)
Faster driver's equation:
(2)
---------------------------
Substitute (1) into (2)
(2)
(2)
(2)
(2)
(2)
and

The speed of the slower driver is 30 mi/hr
The speed of the faster driver is 45 mi/hr
check:
(1)
(1)
(1) mi
and
(2)
(2)
(2)
(2)
OK
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