# SOLUTION: A 3-gallon mixture contains one part S and two parts R. In order to change it to a mixture containing 25% S, how much R should be added?

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 Click here to see ALL problems on Mixture Word Problems Question 621442: A 3-gallon mixture contains one part S and two parts R. In order to change it to a mixture containing 25% S, how much R should be added?Answer by ankor@dixie-net.com(15652)   (Show Source): You can put this solution on YOUR website!A 3-gallon mixture contains one part S and two parts R. In order to change it to a mixture containing 25% S, how much R should be added? : The the resulting amt will be 75% r, do this in per cent r, ignore s A 3 gallon mixture 1:2 will have r in it : let r = no. of gal of r required the mixture equation (3) + r = .75(r+3) 2 + r = .75r + 2.25 r - .75r = 2.25 - 2 .25r = .25 r = 1 gallon required to accomplish this