SOLUTION: express as a single logarithm
log(x^2+2x-3/x^2-4)-log(x^2+7x+6/x+2)
Thank you so much for all your help.
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Question 6137: express as a single logarithm
log(x^2+2x-3/x^2-4)-log(x^2+7x+6/x+2)
Thank you so much for all your help.
Answer by arunpaul(104) (Show Source): You can put this solution on YOUR website!
log(x^2+2x-3/x^2-4)-log(x^2+7x+6/x+2)
=log((x^2+2x-3/x^2-4)/(x^2+7x+6/x+2))
=log[{(x^2+3x-x-3)/((x+2)(x-2))}/{(x^2+6x+x+6)/(x+2)}]
= log [{((x+3)(x-1))/((x+2)(x-2))}/{(x+6)(x+1)/(x+2)}]
= log [{((x+3)(x-1))/(x-2)}/{(x+6)(x+1)}]
(Ans)
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