SOLUTION: How many liters of a 14% alcohol solution must be mixed with 20 liters of a 50% solution to get a 30% solution?
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Question 61047: How many liters of a 14% alcohol solution must be mixed with 20 liters of a 50% solution to get a 30% solution?
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Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
.14X+.5*20=(X+20).3
.14X+10=.3X+6
.14X-.3X=6-10
-.16X=-4
X=-4/-.16
X=25 LITERS OF 14% ALCOHOL.
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