# SOLUTION: a chemist must mix 6 liters of a 30% acid solution with some of an 80% solution to get a 50% acid solution. How many liters of the 80% solution should be used. I think I have th

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 Question 609196: a chemist must mix 6 liters of a 30% acid solution with some of an 80% solution to get a 50% acid solution. How many liters of the 80% solution should be used. I think I have the equation set up correctly: 0.80x + 0.30*6=0.50(x+5) but i honestly don't know how to go from there. Found 2 solutions by ankor@dixie-net.com, Alan3354:Answer by ankor@dixie-net.com(15638)   (Show Source): You can put this solution on YOUR website!0.80x + 0.30*6 = 0.50(x+5) .8x + 1.8 = .5x + 2.5 .8x - .5x = 2.5 - 1.8 .3x = .7 x = x = 2 liters of the 80% stuff Answer by Alan3354(30983)   (Show Source): You can put this solution on YOUR website!a chemist must mix 6 liters of a 30% acid solution with some of an 80% solution to get a 50% acid solution. How many liters of the 80% solution should be used. I think I have the equation set up correctly: 0.80x + 0.30*6=0.50(x+5) -------------- 0.8x + 0.30*6 = 0.50*(x + 6) not x+5, you got it right o/w Solve for x Multiply by 10 to eliminate fractions 8x + 18 = 5x + 30 x = 4 liters