SOLUTION: how many liters of a 30% acid solution must be mixed with 2 liters of a 12% solution to obtain a 15% solution

Algebra.Com
Question 605692: how many liters of a 30% acid solution must be mixed with 2 liters of a 12% solution to obtain a 15% solution
Answer by mathie123(224)   (Show Source): You can put this solution on YOUR website!
For a word problem, the first step is to determine what it is we are trying to solve for. In most cases, once we figure this out we can give it a variable and using the question make an equation using that variable.
In our case, we are trying to solve for the number of litres of the 30% solution. Let's call this x.
Using the question, we can write the following equation:

(This is because we have x litres of 30% solution, adding that to 2 litres of 10% solution should give us x+2 litres of 15% solution-- if this is unclear please email me and I can help you further:) )
So now all that is left to do is solve for x:





This means that there needs to be approximately 4.29 litres of the 30% acid solution mixed.
RELATED QUESTIONS

how many liters of a 10% acid solution must be mixed with a 50% acid solution in order to (answered by ewatrrr)
How many liters of a 20% acid solution must be mixed with a 50 % acid solution in order... (answered by stanbon)
How many liters of a 15% acid solution should be mixed with 30 liters of a 40% acid... (answered by lostin)
How many liters of a 10% acid solution must be mixed with a 50% acid solution in order to (answered by Alan3354)
how many liters of a 10% acid solution must be mixed with a 50% acid solution in order to (answered by checkley75)
How many liters of a 10% acid solution must be mixed with a 50% acid solution in order to (answered by Alan3354)
how many liters of a 10% acid solution must be mixed with a 50% acid solution in order to (answered by Alan3354)
How many liters of 20% acid solution should be mixed with 50% acid solution to obtain 12... (answered by josgarithmetic)
how many liters of a 10% acid solution can be mixed with a 50% acid solution in order to (answered by richwmiller)