SOLUTION: How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get a 90% acid solution?
Algebra.Com
Question 597441: How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get a 90% acid solution?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
6*.2=1.2 total gal of acid.
Let x=gal of pure acid required.
x*1.00=x total gal of acid
(6+x)*0.9=.9(6+x) total gal acid
.
1.2+x=.9(6+x)
1.2+x=5.4+.9x
.1x=4.2
x=42 gallons
.
Ed
RELATED QUESTIONS
How much pure acid should be mixed with 6 gallons of a 10% acid solution in order to get... (answered by ewatrrr)
How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get... (answered by Fombitz)
How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get... (answered by josgarithmetic)
How much pure acid should be mixed with 2 gallons of an 80% acid solution in order to get (answered by oberobic)
How much pure acid should be mixed with 5 gallons of a 40% acid solution in order to get... (answered by stanbon)
How much pure acid should be mixed with 2 gallons of a 60 percent acid solution in order... (answered by stanbon)
How much pure acid should be mixed with 5 gallons of a 70% acid solution in order to get... (answered by mananth)
How much pure acid should be mixed with 5 gallons of a 40% acid solution in order to get... (answered by josmiceli)
How much pure acid should be mixed with 5 gallons of a 40% acid solution in order to get... (answered by josmiceli)