SOLUTION: pure acid is to be added to 10% acid solution to obtain 90L of 53% solution. what amount of each should be used?

Question 592542: pure acid is to be added to 10% acid solution to obtain 90L of 53% solution. what amount of each should be used?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
pure acid is to be added to 10% acid solution to obtain 90L of 53% solution. what amount of each should be used?
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Equation:
acid + acid = acid
x + 0.10(90-x) = 0.53*90
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Multiply thru by 100 to get:
100x + 10*90 - 10x = 53*90
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90x = 43*90
x = 43 L (amt. of pure acid to be added)
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Cheers,
Stan H.
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