SOLUTION: How many liters of 60% alcohol solution and 30% alcohol solution must be mixed to obtain 3 liters of 40% alcohol solution?
Complete the table below, then solve.
Algebra.Com
Question 585248: How many liters of 60% alcohol solution and 30% alcohol solution must be mixed to obtain 3 liters of 40% alcohol solution?
Complete the table below, then solve.
60% solution 30% solution Final solution
Number of Liters x y
Liters of Alcohol
The answer is:
Liters of 60% solution = Liters
Liters of 30% solution = Liters
Answer by sofiyac(983) (Show Source): You can put this solution on YOUR website!
How many liters of 60% alcohol solution and 30% alcohol solution must be mixed to obtain 3 liters of 40% alcohol solution?
60x+30(3-x)=40*3
60x+90-30x=120
30x=30
x=1
1 liter of 60% solution and 3-1=2 liters of 30% solution
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