SOLUTION: How many liters (L) of a 30% alcohol solution must be mixed with 50 L of a 80% solution to get a
50% solution?
Algebra.Com
Question 583099: How many liters (L) of a 30% alcohol solution must be mixed with 50 L of a 80% solution to get a
50% solution?
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
0.30x + 50(0.80) = .50(x + 50)
Can you take it from here?
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