SOLUTION: how many liters of a 50% acid solution must be mixed with a 30% acid solution to get 200 L of a 40% acid solution?
Algebra.Com
Question 577678: how many liters of a 50% acid solution must be mixed with a 30% acid solution to get 200 L of a 40% acid solution?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
percent ---------------- quantity
Acod solution type I 50.00% ---------------- x liters
Acid solution type II 30.00% ------ 200 - x liters
Mixture 40.00% ---------------- 200
50.00% x+30.00%(200-x)=40.00% * 200
50x+30(200-x)= 8000
50x+6000-30x=8000
50x-30x =8000-6000
20x= 2000
/ 20
x= 100 liters 50.00% Acid solution type I
100 liters 30.00% Acid solution type II 50
m.ananth@hotmail.ca
RELATED QUESTIONS
How many liters of a 50% acid solution must be mixed with a 10% acid solution to get 360... (answered by mananth)
How many liters of a 50% acid solution must be mixed with a 15% acid solution to get 350... (answered by ikleyn)
how many liters of 50% acid solution must be mixed with a 30% acid solution to get 180... (answered by mananth)
How many liters of 60% acid solution must be mixed with a 30% acid solution to get 240 L... (answered by ewatrrr)
How many liters of a 50% acid solution must be mixed with a 20% acid solution to get 240... (answered by ewatrrr,richwmiller)
How many liters of a 50% acid solution must be mixed with a 30% acid solution to get 180L (answered by mananth)
How many liters of a 50% acid solution must be mixed with a 25% acid solution to get 225... (answered by richwmiller)
how many liters of a 50% acid solution must be mixed with a 20% acid solution to get 270... (answered by mananth)
how many liters of a 60% acid solution must be mixed with a 10% acid solution to get 400... (answered by checkley79)