# SOLUTION: How many liters of a mixture containing 80% alcohol should be added to 5 liters of 20% alcohol to yeild a 30% alcohol solution?

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 Question 576166: How many liters of a mixture containing 80% alcohol should be added to 5 liters of 20% alcohol to yeild a 30% alcohol solution?Answer by lwsshak3(6505)   (Show Source): You can put this solution on YOUR website!How many liters of a mixture containing 80% alcohol should be added to 5 liters of 20% alcohol to yeild a 30% alcohol solution? ** let x = liters of 80% alcohol to be added 5+x = liters of 30% solution .. 80%x+20%*5=30%(5+x) .8x+1=1.5+.3x .5x=.5 x=1 ans: liters of 80% alcohol to be added = 1