SOLUTION: A CHEMIST HAS TWO SOLUTIONS OF H2SO4. ONE HAS 40% CONCENTRATION AND THE OTHER HAS 25% CONCENTRATION. HOW MANY LITERS OF EACH SOLUTION MUST BE MIXED TO OBTAIN 50 LITERS OF A 27% SOL

Question 574176: A CHEMIST HAS TWO SOLUTIONS OF H2SO4. ONE HAS 40% CONCENTRATION AND THE OTHER HAS 25% CONCENTRATION. HOW MANY LITERS OF EACH SOLUTION MUST BE MIXED TO OBTAIN 50 LITERS OF A 27% SOLUTION? ROUND TO THE NEAREST TENTH IF POSSIBLE
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A CHEMIST HAS TWO SOLUTIONS OF H2SO4. ONE HAS 40% CONCENTRATION AND THE OTHER HAS 25% CONCENTRATION. HOW MANY LITERS OF EACH SOLUTION MUST BE MIXED TO OBTAIN 50 LITERS OF A 27% SOLUTION? ROUND TO THE NEAREST TENTH IF POSSIBLE
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Equation:
active + active = active
0.40x + 0.25(50-x) = 0.27*50
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Multiply thru by 100 to get:
40x + 25*50 - 25x = 27*50
15x = 2*50
x = 100/15 = 6 2/3 liters (amt. of 40% solution needed)
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50-x = 43 1/3 liters (amt. of 25% solution needed)
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Cheers,
Stan H.
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