SOLUTION: 30 gallons of a 20% acid solution is needed for an experiment. Only 40% and 10% acid solution are available. How much of each should be mixed to form the needed solution?

Question 573368: 30 gallons of a 20% acid solution is needed for an experiment. Only 40% and 10% acid solution are available. How much of each should be mixed to form the needed solution?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
30 gallons of a 20% acid solution is needed for an experiment.
Only 40% and 10% acid solution are available.
How much of each should be mixed to form the needed solution?
:
Let x = amt of 40% acid required
the resulting amt is to be 30 gal, therefore:
(30-x) = amt of 10% acid required
:
A typical mixture equation
:
.40x + .10(30-x) = .20(30)
.40x + 3 - .10x = 6
.40x - .10x = 6 - 3
.30x = 3
x =
x = 10 gal of 40% acid
then
30 - 10 = 20 gal of the 10% acid
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