SOLUTION: how many liters of a 80% acid solution must be mixed with a 10% acid solution to get 560liters of a 70% acid solution
Algebra.Com
Question 572980: how many liters of a 80% acid solution must be mixed with a 10% acid solution to get 560liters of a 70% acid solution
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
percent ---------------- quantity
Acid solution Type I 80.00% ---------------- x L
Acid solution type II 10.00% ------ 560 - x L
Mixture 70.00% ---------------- 560
80.00%x+10.00%(560-x)=70.00%*560
80x+10(560-x)= 39200
80x+5600-10x=39200
80x-10x =39200 -5600
70x= 33600
/70
x =480L 80.00% Acid solution Type I
80L 10.00% Acid solution type II
RELATED QUESTIONS
how many liters of a 80% acid solution must be mixed with a 30% acid solution to get 300... (answered by checkley79)
how many liters of 80% acid solution must be mixed with 15% acid solution to get 455 L of (answered by lwsshak3)
How many liters of 70% acid solution must be mixed with 10% acid solution to get 480 L of (answered by stanbon)
how many liters of a 70% acid solution must be mixed with a 30% acid solution to get 400... (answered by josgarithmetic)
how many liters of a 70% acid solution must be mixed with a 15% acid solution to get 385L (answered by Alan3354)
How many liters of a 70% acid solution must be mixed with a 25% acid solution to get 270... (answered by Fombitz)
how many liters of a 70% acid solution must be mixed with a 30% acid solution to get 240... (answered by macston)
How many liters of a 70% acid solution must be mixed with a 25% acid solution to get 315... (answered by josgarithmetic)
How many liters of a 70% acid solution must be mixed with a 15% acid... (answered by josgarithmetic)