SOLUTION: How many centiliters of a 25% acid solution must be added to 200 centiliters of a 4% acid solution to make a 10% acid solution?

Question 565209: How many centiliters of a 25% acid solution must be added to 200 centiliters of a 4% acid solution to make a 10% acid solution?
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Solution A
Amount = x
Concentration =25% = 0.25

Solution B
Amount = 200
Concentration =4% = 0.04

Resultant Solution
Amount = 200+x
Concentration =10% = 0.1

[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B]+ [Amount Solution B * Concentration of B] = Amount of Resultant * Concentration of resultant
(0.25)(x)+(200)(0.04)=(200+x)(0.1)
0.25x+8=20+0.1x
0.25x-0.1x=20-8
0.15x=12
0.15x/0.15=12/0.15
x=80

Solution A
Amount = x = 80 centiliters
Concentration =25% = 0.25

Solution B
Amount = 200 centiliters
Concentration =4% = 0.04

Resultant Solution
Amount = 200+x = 200+80 = 280 centiliters
Concentration =10% = 0.1

80 centiliters of a 25% acid solution must be added to 200 centiliters of a 4% acid solution to make a 10% acid solution.

RELATED QUESTIONS
How many centiliters of pure acid must be added to 200 cl of a 40% acid solution to... (answered by macston)

A chemical store room has a 90% acid solution and 40% solution. How many CENTILITERS of... (answered by jim_thompson5910)

How many liters of a 60% acid solution must be added to 10 liters of 20% acid solution to (answered by nerdybill)

How many liters of a 50% acid solution must be added to 10 liters of a 15% acid solution... (answered by ewatrrr)

How many liters of a 50% acid solution must be added to 10 liters of a 15% acid solution... (answered by josmiceli)

How many liters of a 50% acid solution must be added to 10 liters of a 15% acid solution... (answered by josgarithmetic)

To make a 6% acid solution, a chemist mixes some 4% acid solution with 12 L of 10% acid... (answered by josgarithmetic,greenestamps)

How many liters of pure acid should be added to 4 liters of a 10% acid solution to make a (answered by richwmiller)