SOLUTION: How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 50% antifreeze?
Can you explain to me how to do this?
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Question 563112: How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 50% antifreeze?
Can you explain to me how to do this?
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
(60%)(x) + (25%)(80) = (50%)(x + 80)
the sum of the amounts of antifreeze in the two solutions to be mixed, equals the amount of antifreeze in the final mixture
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