SOLUTION: I have some mixture problems i need help with. Can you please help me? I have to use a formula %*amount=product Gus has on hand a 5% alcohol solution and a 20% alcohol solut

Question 561723: I have some mixture problems i need help with. Can you please help me?
I have to use a formula %*amount=product
Gus has on hand a 5% alcohol solution and a 20% alcohol solution. He needs 30 liters of a 10% alcohol solution. How many liters of each solution should he mix together to obtain the 30 liters?

My table i made is
Liters % total liters
5% sol. x-.05 .05 .05x
20% sol. y .20 .20y
mixture x+y=10 .01

Can you please help me know what I should do or what I did wrong?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Gus has on hand a 5% alcohol solution and a 20% alcohol solution.
He needs 30 liters of a 10% alcohol solution.
How many liters of each solution should he mix together to obtain the 30 liters?
:
There is an easier way to do this
let x = 20% solution
then since the result is to be 30 liter:
(30-x) = 5% solution
:
A typical mixture equation
:
.20x + .05(30-x) = .10(30)
.20x + 1.5 - .05x = 3
.20x - .05x = 3 - 1.5
.15x = 1.5
x =
x = 10 liters of 20% solution
then
30-10 = 20 liters of 5% solutions
:
;
Check this
.2(10) + .05(20) = .10(30)
2 + 1 = 3; confirms our solutions solution of 10 and 20
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