SOLUTION: What quantity of 80 per cent acid solution must be mixed with a 25 percent solution to produce 528 mL of a 50 per cent solution?

Question 560136: What quantity of 80 per cent acid solution must be mixed with a 25 percent solution to produce 528 mL of a 50 per cent solution?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What quantity of 80 per cent acid solution must be mixed with a 25 percent solution to produce 528 mL of a 50 per cent solution?
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Equation:
acid + acid = acid
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0.80x + 0.25(528-x) = 0.50*528
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Multiply thru by 100 to get:
80x + 25*528 - 25x = 50*528
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55x = 25*528
x = (5/11)528
x = 240 mL (amt. of 80% solution needed)
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Cheers,
Stan H.
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