SOLUTION: Can you please help, I am not coming up with the correct solution. PROBLEM: The label on the listerine is 21.6% alcohol by volume, the Scope is 15% alcohol by volume, Hans mixes

Question 55920This question is from textbook Elementary Algebra for College Students
: Can you please help, I am not coming up with the correct solution.
PROBLEM: The label on the listerine is 21.6% alcohol by volume, the Scope is 15% alcohol by volume, Hans mixes 6 oz of Listerine with 4 oz of Scope. What is the percent alcohol content of the mixture?
6(.216)+4(.15)=10x
1.30+.60=10x
1.90=10x WHAT AM I MISSING / DOING WRONG? This question is from textbook Elementary Algebra for College Students

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The label on the listerine is 21.6% alcohol by volume, the Scope is 15% alcohol by volume, Hans mixes 6 oz of Listerine with 4 oz of Scope. What is the percent alcohol content of the mixture?
---------------
By the way; your work looks good. Divide 1.9 by 10 and get 0.19
or 19%
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Lesterine DATA:
amount is 6 oz ; amount of alcohol is 0.216(6)= 1.296 oz
--------
Scope DATA:
amount is 4 oz ; amount of alcohol is 0.15(4)=0.6 oz
----------
Misture DATA:
amount is 6+4= 10 oz ; amount of alcohol is x(10)= 10x
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EQUATION:
alcohol + alcohol = alcohol
1.296 + 0.6 = 10x
1.896=10x
x=0.1896 or 18.96%
Cheers,
Stan H.

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