SOLUTION: how much of a (n) 90% orange juice drink must be mixed with 16 gallons of a 30% orange juice drink to obtain a mixture that is 50% orange juice?

Question 558821: how much of a (n) 90% orange juice drink must be mixed with 16 gallons of a 30% orange juice drink to obtain a mixture that is 50% orange juice?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
percent ---------------- quantity
Orange juice type I 30----------------16 gallons
Orange juice type II 90----------------x gallons
Mixture 50----------------20+x gallons

30*16+90x=50(20+x)
480+90x =1000+50x
90x-50x=1000-480
40 x = 520
/ 40
x= 13 gallons of Orange juice type II

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