SOLUTION: How many gallons of a 50% alcohol solution must be mixed with 80 gallons of a 14% solution to obtain a solution that is 40% alcohol?
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Question 555789: How many gallons of a 50% alcohol solution must be mixed with 80 gallons of a 14% solution to obtain a solution that is 40% alcohol?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
.5x+80*.14=.4*(80+x)
.5x+80*.14=.4*80+.4x
.1x=.4*80-80*.14
.1x=80*(.4-.14)
.1x=80*(.26)
multiply by 10
x=80*2.6
x=208 gallons
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