SOLUTION: a man mixes 100 lbs of 90% copper alloy with 150 lbs of 60% copper alloy what is his percentage of the total copper alloy?
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Question 549304: a man mixes 100 lbs of 90% copper alloy with 150 lbs of 60% copper alloy what is his percentage of the total copper alloy?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a man mixes 100 lbs of 90% copper alloy with 150 lbs of 60% copper alloy what is his percentage of the total copper alloy?
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Equation:
copper + copper = copper
0.90*100 + 0.60*150 = x(100+150)
Multiply thru by 100 to get:
90*100 + 60*150 = x(25000)
25000x = 9000+9000
x = 0.72 = 72%
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Cheers,
Stan H.
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