SOLUTION: A container has 6 liters of a 40% solution of alcohol in it. How much pure alcohol should be added to raise it to a 60% solution. I have a test today and i dont understand mixtu

Question 548187: A container has 6 liters of a 40% solution of alcohol in it. How much pure alcohol should be added to raise it to a 60% solution.
I have a test today and i dont understand mixture problems very well and i was hoping you could be my lifesaver and help me learn this before i have to go to school :)
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
A container has 6 liters of a 40% solution of alcohol in it. How much pure alcohol should be added to raise it to a 60% solution.
.
Let x = amount (liters) of pure (100%) alcohol
then
"amt added" + "amt of alcohol at star" = "new percentage"
x + .40(6) = .60(x+6)
x + 2.4 = .60x+3.6
.40x + 2.4 = 3.6
.40x = 1.4
x = 1.4/.40
x = 3.5 liters

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