SOLUTION: How many liters of pure acid must be added to 5L of a solution that is 20% acid to make a solution that is 60% acid?
x+0.2 (5)= 0-6 (x=5)
x=1= o.6x+3
-0.6x-1-0.6x-1
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Question 540371: How many liters of pure acid must be added to 5L of a solution that is 20% acid to make a solution that is 60% acid?
x+0.2 (5)= 0-6 (x=5)
x=1= o.6x+3
-0.6x-1-0.6x-1
____________________
0.4x=2
______
0.4 0.4
x=5
Does my work look correct?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = liters of pure acid needed
given:
liter od pure acid in 20% solution
5 liters of pure acid is needed
check:
OK
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I'm not sure how you did it, but this is how
I do all these kind of problems. Same answer.
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