# SOLUTION: Question: How much of a 50% acid solution must be mixed with 80 gallons of a 14% acid solution to obtain a solution that is 40% acid? Answer Options: A. 11.2gal C.112gal

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 Question 523532: Question: How much of a 50% acid solution must be mixed with 80 gallons of a 14% acid solution to obtain a solution that is 40% acid? Answer Options: A. 11.2gal C.112gal B.208gal D.None of these<----wrong answer(known) Tried: .5x+80(.14)=.40 .14+.40=.5xAnswer by ankor@dixie-net.com(15649)   (Show Source): You can put this solution on YOUR website!How much of a 50% acid solution must be mixed with 80 gallons of a 14% acid solution to obtain a solution that is 40% acid? : Where x is amt of 50% solution required, the equation should be .50x + .14(80) = .40(x+80)