SOLUTION: find the real solutions. (2x+5)^2-(2+5)-6=0 thanks Caroline

Question 5221: find the real solutions.
(2x+5)^2-(2+5)-6=0
thanks Caroline
Answer by ichudov(507) (Show Source): You can put this solution on YOUR website!
I have a hunch that you forgot an 'x' and meant

use y instead of 2x+5, to get

solve it for y:

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=25 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 3, -2. Here's your graph:

y=3, y=-2, or, knowing that y=2x+5, you have two equations
2x+5 = 3, or 2x=-2, or x = -1
2x+5 = -2, or 2x=-7, or x = -3.5.
Double check my answer please.
Answer: x=-1, x=-3.5
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