# SOLUTION: You need a 80% alcohol solution. On hand, you have a 320 mL of a 85% alcohol mixture. How much pure water will you need to add to obtain the desired solution? You will need m

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: You need a 80% alcohol solution. On hand, you have a 320 mL of a 85% alcohol mixture. How much pure water will you need to add to obtain the desired solution? You will need m      Log On

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 Click here to see ALL problems on Mixture Word Problems Question 521471: You need a 80% alcohol solution. On hand, you have a 320 mL of a 85% alcohol mixture. How much pure water will you need to add to obtain the desired solution? You will need mL of pure water to obtain mL of the desired 80% solution.Found 2 solutions by stanbon, richwmiller:Answer by stanbon(57282)   (Show Source): You can put this solution on YOUR website!You need a 80% alcohol solution. On hand, you have a 320 mL of a 85% alcohol mixture. How much pure water will you need to add to obtain the desired solution? ---------- Equation: alcohol + alcohol = alcohol 0.85*320 + 0*x = 0.80(320+x) ---- Multiply thru by 100 to get: 85*320 + 0 = 80*320 + 80x 5*320 = 80x x = 20 mL (amt. of pure water needed) ------------------------------------------ Cheers, Stan H. ============ Answer by richwmiller(9135)   (Show Source): You can put this solution on YOUR website!from the view of water 320*.15+w=(320+w)*.20 w=20 ml of water from the view of alcohol .85*320=.80*(320+w) w=20 ml of water