SOLUTION: The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturor of the antifreeze suggests that, for summer driving, optimal cooling of the engine

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Question 52068: The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturor of the antifreeze suggests that, for summer driving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the radiator is 3.6Liters how much coolant should be drained and replaced with water to reduce the antifreeze concentration to the recommended level.
Answer by josmiceli(6786) About Me  (Show Source):
You can put this solution on YOUR website!
How much of the amount to be removed is antifreeze?
Call the amount to be removed and repaced with water
w
.6w of that is antifreeze
I started out with .6%2A3.6+=+2.16 liters antifreeze
I'm losing .6w liters
%282.16+-+.6w%29+%2F+3.6+=+.50
3.6%2A.50+=+2.16+-+.6w
1.8+=+2.16+-.6w
.6w+=+2.16+-+1.8
.6w+=+.36
w+=+.6 liters removed and replaced with water
check
How much water is there now?
.40%2A3.6+=+1.44 liters was unaffected by what we did
.6%2A.6+=+.36 liters is the alcohol that was replaced with water
1.44+%2B+.36+=+1.8 liters of water now
How much antifreeze is there now?
.60%2A3.6+-+.60%2A.6 liters
2.16+-+.36 =
1.8 liters antfreeze now
That's a 50-50 mixture as it should be