# SOLUTION: Pure acid is to be added to a 10% acid solution to obtain 90L of 60% solution. What amounts of each should be used? How many liters of 100% pure acid should be used to make the

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 Question 517994: Pure acid is to be added to a 10% acid solution to obtain 90L of 60% solution. What amounts of each should be used? How many liters of 100% pure acid should be used to make the solution? How many liters of the 10% solution should be used in the mixture?Answer by stanbon(57219)   (Show Source): You can put this solution on YOUR website!Pure acid is to be added to a 10% acid solution to obtain 90L of 60% solution. What amounts of each should be used? How many liters of 100% pure acid should be used to make the solution? Equation: 1.00x + 0.10(90-x) = 0.6*90 --- 100x + 10*90 - 10x = 60*90 --- 90x = 50*90 x = 50 L (amt. of pure acid needed) ============================================= How many liters of the 10% solution should be used in the mixture? 90-x = 90-50 = 40L (amt of 10% solution needed. ================================================= Cheers, Stan H. ============