SOLUTION: How many liters of a 60% solution should be added to 50 liters of a 30% solution to obtain a 40% solution?

Question 512980: How many liters of a 60% solution should be added to 50 liters of a 30% solution to obtain a 40% solution?
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Soluton A
Amount = x
Concentration = 60%=0.6
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Solution B
Amount = 50 liters
Concentration = 30%=0.3
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Resultant Solution
Amount=50+x
Concentration=40%=0.4
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(Amount of A * Concentration of A)+(Amount of B * Concentration of B) = (Amount of Resultant * Concentration of Resultant)
(x*0.6)+(50*0.3)=(50+x)*0.40
0.6x+15=20+0.4x
0.6x-0.4x=20-15
0.2x=5
0.2x/0.2=5/0.2
x=50
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50 liters of a 60% solution should be added to 50 liters of a 30% solution to obtain a 40% solution?
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