# SOLUTION: chemical is 60% acid and chemical B is 36% acid. How much of each should be mixed together to get 120oz of a chemical that is 52% acid?

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 Question 510304: chemical is 60% acid and chemical B is 36% acid. How much of each should be mixed together to get 120oz of a chemical that is 52% acid?Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!With mixture problems, you need to keep track of how much 'pure' stuff you have or need. . 120 oz. of a 52% solution means you need to have .52*120 = 62.4 oz of 'pure' acid in the 120 oz. . You will combine an unknown amount of one solution, 'x' with another amount to have 120 oz. So we can use x' and '120-x' as the two volumes. . The combined solutions are defined by the following equation. . 60%*x + 36%(120-x) = 52%*120 . Solve it. . .60x + .36(120-x) = .52*120 . multiply by 100 to eliminate decimals . 60x + 36(120-x) = 52*120 . 60x +4320 -36x = 6240 . 24x = 6240 -4320 . 24x = 1920 . x = 80 oz 120-x = 40 oz . Answer: Combine 80 oz. of 60% solution and 40 oz. of 36% solution. . Check to be sure the answer is right. . 60%(80 oz) = 48 oz of 'pure' acid 36%(40 oz) = 14.4 oz of 'pure' acid 48 + 14.4 = 62.4 oz. of 'pure' acid in the 120 oz., which is what we need to achieve 52% . Done.