SOLUTION: A radiator contains 13 quarts of fluid, 25% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 50% antifreeze?

Question 510000: A radiator contains 13 quarts of fluid, 25% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 50% antifreeze?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A radiator contains 13 quarts of fluid, 25% of which is antifreeze.
How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 50% antifreeze?
:
Let x = amt of original antifreeze to be drained, and the amt of pure antifreeze to be added
:
a simple equation
.25(13-x) + x = .50(13)
3.25 - .25x + x = 6.5
-.25x + 1x = 6.5 - 3.25
.75x = 3.25
x = 3.25/.75
x = 4 quarts removed, then the same amt of pure antifreeze added
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