# SOLUTION: how many liters of a 25% alcohol solution must be mixed with a 12% solution to get 13L of a 15% solution?

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 Question 509652: how many liters of a 25% alcohol solution must be mixed with a 12% solution to get 13L of a 15% solution?Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!---------percent ---------------- quantity Alcohol I 25 ---------------- x liters Alcohol II ---------------- 13 - x liters Mixture ---------------- 13 25x+12(13-x)=15*13 25x+156-12x=195 25x-12x=195-156 13x=39 / 13 x = 3 liters 25.00% Alcohol I 10 liters 12.00% Alcohol II