SOLUTION: I have a mixture prolem to find 15 milliliters of a solution that is 2% active ingredient and I have a 10% and 1% solotion in my stock. How do i get 2% solution?

Question 509098: I have a mixture prolem to find 15 milliliters of a solution that is 2% active ingredient and I have a 10% and 1% solotion in my stock. How do i get 2% solution?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
I have a mixture problem to find 15 milliliters of a solution that is 2% active ingredient and I have a 10% and 1% solution in my stock.
How do i get 2% solution?
:
let x = amt of 10% solution
The resulting amt is to be 15 ml, therefore
(15-x) = amt of 1% solution
:
.10x + .01(15-x) = .02(15)
.10x + .15 - .01x = .3
.10x - .01x = .3 - .15
.09x = .15
x =
x = 1 ml of 10% solution
and
15 - 1 = 13 ml of 1% solution
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