# SOLUTION: how much of an 80% orange juice drink must be mized with 20 gallons of a 20% orange juice drink to obtain a mixture that is 50% orange juice

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 Click here to see ALL problems on Mixture Word Problems Question 503047: how much of an 80% orange juice drink must be mized with 20 gallons of a 20% orange juice drink to obtain a mixture that is 50% orange juiceAnswer by mananth(12270)   (Show Source): You can put this solution on YOUR website! --------percent ---------------- quantity Orange juice 20 ---------------- 20 gal Orange juice 80 ---------------- x gal Mixture 50 ---------------- 20 + x gal 20 * 20 + 80 x = 50 ( 20 + x ) 400 + 80 x = 1000 + 50 x 80 x + -50 x = 1000 - -400 30 x = 600 / 30 x = 20 20 gal of 80 % Orange juice