SOLUTION: The sum of the reciprocals of two consecutive even integers a and b is
9/40
. Find the integers.
Algebra.Com
Question 502957: The sum of the reciprocals of two consecutive even integers a and b is
9/40
. Find the integers.
Answer by jrb1965(16) (Show Source): You can put this solution on YOUR website!
a and b are two consecutive even integers so b = a + 2
1/a + 1/(a+2) = 9/40
Multiply all terms by (a+2)* a * 40
40(a+2) + 40a = 9(a+2)a
40a + 80 + 40a = 9a^2 + 18a
Rearrange to the quadratic
a = 8
b = 10
RELATED QUESTIONS
The sum of the reciprocals of two consecutive even integers a and b is
7 over 24
.... (answered by htmentor)
Solve and verify your answer.
The sum of the reciprocals of two consecutive even... (answered by ankor@dixie-net.com,greenestamps)
the sum of the reciprocals of two consecutive even integers is 9/40. what are the... (answered by mananth)
the sum of the reciprocals of two consecutive even integers is 9/40. what are the... (answered by CubeyThePenguin)
The sum of the reciprocals of two consecutive even integers is 11/60. Find the... (answered by funmath)
The sum of the reciprocals of two consecutive even integers is 11/60. Find the... (answered by ankor@dixie-net.com)
The sum of the reciprocals of two consecutive even integers is 5/12.
Find the... (answered by josgarithmetic,Alan3354,greenestamps)
The sum of the reciprocals of two consecutive even integers is 7/24. Find these... (answered by checkley77)
the sum of the reciprocals of two consecutive even integers is 13/84 .find these... (answered by lwsshak3)