SOLUTION: Two solutions, one containing 4.5% iodine and the other containing 12% iodine, are to be mixed to produce 10 liters of a 6% iodine solution. How many liters of each are required?

Question 501534: Two solutions, one containing 4.5% iodine and the other containing 12% iodine, are to be mixed to produce 10 liters of a 6% iodine solution. How many liters of each are required?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = liters of 4.5% solution needed
Let = liters of 12% solution needed
given:
= iodine in 4.5% solution
= iodine in 12% solution
-----------
(1)
(2)
--------------------------
(2)
Multiply both sides of (2) by
(2)
Divide both sides by
(2)
Multiply both sides of (1) by , and
subtract (1) from (2)
(2)
(1)

and, since
(1)
(1)
(1)
8 liters of 4.5% solution are needed
2 liters of 12% solution are needed
--------
check:
(2)
(2)
(2)
(2)
(2)
OK
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