SOLUTION: how many liters of pure water should be mixed with a 3-L solution of 80% acid to produce a mixture that is 70% water?

Question 500673: how many liters of pure water should be mixed with a 3-L solution of 80% acid to produce a mixture that is 70% water?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
how many liters of pure water should be mixed with a 3-L solution of 80% acid to produce a mixture that is 70% water?
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Let w = amt of pure water required to accomplish this
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Write an amt of acid equation, acid amt remains the same, only the percent changes
.80(3) = .70(w+3)
2.4 = .7w + 2.1
2.4 - 2.1 = .7w
.3 = .7w
w =
w = .42857 liters of pure water
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