# SOLUTION: A radiator contains 15 quarts of fluid, 40% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A radiator contains 15 quarts of fluid, 40% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze?       Log On

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 Question 500050: A radiator contains 15 quarts of fluid, 40% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze? Answer by mananth(12269)   (Show Source): You can put this solution on YOUR website! percent ---------------- quantity Antifreeze I 40 ---------------- 5 quarts Antifreeze II 100 ---------------- x quarts Mixture 60 ---------------- 15 + x quarts 40 * 5 + 100 x = 60 ( 15 + x ) 200 + 100 x = 900 + 60 x 100 x + -60 x = 900 - -200 40 x = 700 / 40 x = 17.5 17.5 quarts of 100 % Antifreeze II So 17.5 quarts has to be drained m.ananth@hotmail.ca