# SOLUTION: Given the numbers 1 - 9; arrange them so that the sum of two 3-digit numbers equals a 3 digit number

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 Question 498997: Given the numbers 1 - 9; arrange them so that the sum of two 3-digit numbers equals a 3 digit number Found 2 solutions by chessace, elrazky1:Answer by chessace(471)   (Show Source): You can put this solution on YOUR website!Cool problem! Can't be done! Sum 1 to 9 is 45. The sum of all the digits of the 1st two 3 digit numbers + possible carry= sum of 3 "answer" digits. If there is no carry, these 2 "equal" sums add to an even number, not 45. So there must be a carry. And the "answer" digits must sum to 23. Only way is 9 8 6 and to get a carry, 9 would have to be on top too. Answer by elrazky1(1)   (Show Source): You can put this solution on YOUR website! 318+249=567