SOLUTION: Given the numbers 1 - 9; arrange them so that the sum of two 3-digit numbers equals a 3 digit number

Question 498997: Given the numbers 1 - 9; arrange them so that the sum of two 3-digit numbers equals a 3 digit number
Found 2 solutions by chessace, elrazky1:
Answer by chessace(471) (Show Source): You can put this solution on YOUR website!
Cool problem!
Can't be done!
Sum 1 to 9 is 45.
The sum of all the digits of the 1st two 3 digit numbers + possible carry=
sum of 3 "answer" digits.
If there is no carry, these 2 "equal" sums add to an even number, not 45.
So there must be a carry.
And the "answer" digits must sum to 23.
Only way is 9 8 6 and to get a carry, 9 would have to be on top too.

Answer by elrazky1(1) (Show Source): You can put this solution on YOUR website!

318+249=567
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