SOLUTION: How much water must you add to a 40 L 80% acid solution to reduce it to 20% acid?

Question 495150: How much water must you add to a 40 L 80% acid solution to reduce it to 20% acid?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How much water must you add to a 40 L 80% acid solution to reduce it to 20% acid?
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Equation:
water + water = water
0.20*40 + x = 0.80(40+x)
Multiply thru by 100 to get:
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20*40 + 100x = 80*40 + 80x
20x = 60*40
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x = 120 L (amt. of water to be added)
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Cheers,
Stan H.
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