SOLUTION: (1 pt) What quantity of 65 per cent acid solution must be mixed with a 30 percent solution to produce 630 mL of a 50 per cent solution?

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Let = ml of 65% solution needed
Let = ml of 30% solution needed
given:
= acid in 65% solution
= acid in 30% solution
(1) ml
-------------------------
(2)
(2)
(2)
(2)
Multiply both sides of (1) by and subtract (1) from (2)
(2)
(1)


and, since
(1)
(1)
(1)
360 ml of 65% solution are needed
270 ml of 30% solution are needed
check answer:
(2)
(2)
(2)
(2)
(2)
OK