SOLUTION: given A={1,3,5,7},B={2,3,5},C={3,4,5,6} evaluate each set. a)A intersected B b)A U C c)B U C d)(A U B) intersected C e)A U (B U C) f)(A intersected B) intersected C G)(A int

Question 481552: given A={1,3,5,7},B={2,3,5},C={3,4,5,6} evaluate each set.
a)A intersected B
b)A U C
c)B U C
d)(A U B) intersected C
e)A U (B U C)
f)(A intersected B) intersected C
G)(A intersected B) U C
any help will be appreciated.
Thank you,
JB
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
a.....
A = {1,3,5,7}
B = {2,3,5}
C = {3,4,5,6}
A intersect B = {3,5}
These are the elements that are in both A and B.
b.....
A = {1,3,5,7}
B = {2,3,5}
C = {3,4,5,6}
A union C = {1,3,4,5,6,7}
These are the elements that are either in A or in B. They do not have to be in both, but can be.
c.....
A = {1,3,5,7}
B = {2,3,5}
C = {3,4,5,6}
B union C = {2,3,4,5,6}
These are the elements that are either in B or in C. They do not have to be in both, but can be.
d.....
A = {1,3,5,7}
B = {2,3,5}
C = {3,4,5,6}
(A union B) = {1,2,3,5,7}
C = {3,4,5,6}
(A union B) intersect C = {3,5}
These are the elements that are in A or B, and are also in C.
e.....
A = {1,3,5,7}
B = {2,3,5}
C = {3,4,5,6}
(B union C) = {2,3,4,5,6}
A union (B union C) = {1,2,3,4,5,6,7}
These are the elements that are in B or in C or in A. They do not have to be common to any of the sets, but can be.
f.....
A = {1,3,5,7}
B = {2,3,5}
C = {3,4,5,6}
A intersect B = {3,5}
(A intersect B) intersect C = {3,5}
These are the elements that are common to A and B and C.
g.....
A = {1,3,5,7}
B = {2,3,5}
C = {3,4,5,6}
A intersect B = {3,5}
(A intersect B) union C = {3,4,5,6}
The are the elements that are common to both A and B or are in C.
-----
A union B means the elements are either in A or in B. They do not have to be in both, but they can be.
A intersect B means the same elements have to be in both A and B.
when you see something like (A intersect B) union C, you need to process the sets that are in the parentheses first and then process outwards.
you find the set that is A intersect B first.
then you find the set that is (A intersect B) union C.
if we had found A intersect B and called it D, then (A intersect B) union C would have been the same as D union C.

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