SOLUTION: How much pure alcohol must be added to 10 gallons of 35% alcohol to have a solution that is 60% alcohol? Solve by substitution method

Question 478960: How much pure alcohol must be added to 10 gallons of 35% alcohol to have a solution that is 60% alcohol? Solve by substitution method
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let x = the number of gallons of pure alcohol to be added to the 10 gallons of 35% alcohol solution to obtain (10+x) gallons of 60% alcohol solution.
You can write the equation for the amount of alcohol as follows (after changing the percentages to their decimal equivalents):
Simplify and solve for x.

Subtract 0.6x from both sides.
Subtract 3.5 from both sides.
Finally, didvide oth sides by 4.
gallons of pure alcohol.
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